In article <a1g8h3lefs8sjlkbshrcr4n734oi9gn4h8@[EMAIL PROTECTED]
>,
Bob <bbx107.XYZ@[EMAIL PROTECTED]
> wrote:
> On Mon, 15 Oct 2007 15:50:50 -0700, ickivickihoffman@[EMAIL PROTECTED]
> wrote:
>
> >So, I need to know what the equation would be to solve this problem.
> >I don't want the answer or anything, just the STARTING equation.
> >
> >"Terry has walked 3 miles. He averages 4 mi/hr. In how many more hours
> >will he have walked 13 miles?"
> >
> >Please just reply with the starting equation, thanks!
>
> distance = rate * time
>
> Now, think about how it applies here. That is the point of the
> question.
And remember to keep the units straight. E.g.
x mi/hr * y hr = x*y mi.
You can treat the units in an expression as additional terms multiplied
with the values, and you multiply and divide the units as you multiply
and divide the expressions.
If you find yourself (e.g) trying to add mi/hr and mi, you have an error
somewhere in your manipulations.
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| BBB b \ Barbara at LivingHistory stop co stop uk
| B B aa rrr b |
| BBB a a r bbb | Quidquid latine dictum sit,
| B B a a r b b | altum viditur.
| BBB aa a r bbb |
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