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Education > Algebra help > Re: Help with a...
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Re: Help with an equation please

by "Greg Neill" <gneillREM@[EMAIL PROTECTED] > Oct 24, 2007 at 04:21 PM

"Dougsd1r" <dougsdir@[EMAIL PROTECTED]
> wrote in message
news:1193230117.800631.320390@[EMAIL PROTECTED]
> How do I fully solve this equation?
>
> x^3 + x^2 -5x + 3 = 0
>
> According to MS Math there are three solutions x=-3, x=1 and x=1
>
> here is what i have so far:
>
> x^3 + x^2 -5x = -3
>
> (x)(x^2 + x - 5) = -3
>
> now im stuck :( any helpers?

Leave the right hand side (of the original) alone
and factor the left hand side.  With a polynomial,
you can sometimes find at least one root by just
looking at the coefficients.  Here the coefficient
of the leading term (x^3) is 1 and the constant
coefficient is 3, so try +/- 1*3, that is, +3 and
-3 in the equation.
 




 6 Posts in Topic:
Help with an equation please
Dougsd1r <dougsdir@[EM  2007-10-24 12:52:09 
Re: Help with an equation please
"Greg Neill" &l  2007-10-24 16:21:04 
Re: Help with an equation please
"Brian M. Scott"  2007-10-24 17:17:45 
Re: Help with an equation please
Stan Brown <the_stan_b  2007-10-24 17:48:56 
Re: Help with an equation please
Dougsd1r <dougsdir@[EM  2007-10-25 09:24:08 
Re: Help with an equation please
"Greg Neill" &l  2007-10-25 08:26:06 

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tan12V112 Sun Oct 12 7:35:17 CDT 2008.