On Jan 27, 2:54=A0pm, "Greg Neill" <gneill...@[EMAIL PROTECTED]
> wrote:
> "Tallison" <Tallison.Rau...@[EMAIL PROTECTED]
> wrote in message
>
>
news:037f548d-334f-43a5-9593-937005da0ff8@[EMAIL PROTECTED]
>
> > The questionut: =A0How many five-card combinations of a standard
playing=
> > card deck have cards from exactly two suits?
>
> > The answer: =A0379,236.
>
> > The sad thing is that after working on this problem for the last hour,
> > I've gotten answers ranging from 32,712 to 65,780 to 268,382.4 (no
> > kidding!) to 328,900 - everything, that is, but the actual answer
> > according to the textbook.
>
> > So for the love of God, can someone help me identify the correct
> > formula?????
>
> The textbook answer looks low to me. =A0Can you specify
> precisely what a "five-card combination" is and what would
> make one unique?
>
> What approaches have you tried?
The five card combination represents a standard poker hand. Brian's
answer above I think nails it. I was stuck on the sum of the "a"
through "d" products, not mindful of the possible two card
combinations by which it needed to be multiplied...
I otherwise looove combination/permutation, probability and set
problems. No doubt I'll be back to this forum.
Thanks! -Tallison
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