On Sun, 17 Feb 2008 05:17:39 -0800 (PST), kukuuk
<sple_gol@[EMAIL PROTECTED]
> wrote in
<news:0d31605f-d600-4de1-b7ba-807d8a1bfa57@[EMAIL PROTECTED]
>
in alt.algebra.help:
> pls po ano po solution po nito?
> 1: solve for g r=gs/g + s tapos dapat ang sagot niya ay
> g = rs/s - r
The language appears to be Tagalog, which I don't read, but
<dapat> is 'must, ought', <ang sagot> is 'the solution',
<ay> is the copula ('to be'), and <tapos> might be 'correct'
(if it's related to <tapat> 'faithful, honest'), so I'm
guessing that this says roughly 'the correct solution is
supposed to be g = rs/s - r' and that this post is a request
for explanations of the solutions.
The problem cannot be solved as it is written here; I think
that some parentheses have been omitted, and that the
original equation should read r = gs/(g + s), with
g = rs/(s - r) as the answer.
Multiply both sides of the equation by g + s:
r(g + s) = gs
Multiply out the left-hand side:
rg + rs = gs
Subtract rg from both sides to get all instances of g on the
same side of the equation:
rs = gs - rg = gs - gr
Factor out g:
rs = g(s - r)
Divide both sides by s - r:
rs/(s - r) = g.
> 2: solve for p t=rn + mn/p tapos dapat ang sagot niya ay
> p = mn/t - rn
The answer is missing parentheses: it should be
p = mn/(t - rn).
Subtract rn from both sides of the equation:
t - rn = mn/p
Multiply both sides by p:
p(t - rn) = mn
Divide both sides by t - rn:
p = mn/(t - rn)
> 3. solve fo m ab/c - 1/2m = 0 tapos dapat ang sagot niya ay
> m = c/2 ab
The original equation should be ab/c - 1/(2m) = 0, and the
answer should be m = c/(2ab).
Start by adding 1/(2m) to both sides of the equation:
ab/c = 1/(2m)
Multiply both sides by m to get it out of the denominator:
abm/c = 1/2
Multiply both sides by c:
abm = c/2
Divide both sides by ab:
m = c/(2ab).
Brian
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