by Paul Sperry <plsperry@[EMAIL PROTECTED]
>
Feb 19, 2008 at 08:05 PM
In article
<90da6086-9c08-41c3-adee-2374818edebd@[EMAIL PROTECTED]
>,
Citizen <FlammesSombres@[EMAIL PROTECTED]
> wrote:
> Hi, can anyone please help with this question?
>
> If a matrix has r pivot columns, how do you know that its trans****t
> also has r pivot columns?
>
> Thanks for your help
How you do this depends on what you know. Here is one way:
Let A be m x n. N( ) = null space; C( ) = column space;
R( ) = row space; A' means the transpose of A.
n = dim(N(A)) + dim(C(A))
= (n - r) + r
= (n - r) + dim(R(A)).
On the other hand, let s be the rank of A'.
m = dim(N(A')) + dim(C(A))
= (m - s) + s
= (m - s) + dim(R(A'))
= (m - s) + dim(C(A))
= (m - s) + r
So, s = r.
--
Paul Sperry
Columbia, SC (USA)