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Re: solving algebraic equations

by Virgil <Virgil@[EMAIL PROTECTED] > Feb 21, 2008 at 01:08 AM

In article <fcednVlTC70BjyDanZ2dnUVZ_uGknZ2d@[EMAIL PROTECTED]
>,
 OP <facetious_nickname@[EMAIL PROTECTED]
> wrote:

> On p. 58 & 59 of Spivak's Calculus, he says "Given two distinct 
> points (a,b) and (c,d), find the linear function f whose graph goes 
> through (a,b) and (c,d). This amounts to saying that f(a) = b and 
> f(c) = d. If f is to be of the form f(x) = Aa + B, then we must have:
> 
> Aa + B = b;
> Ac + B = d;
> 
> therefore A = (d - b)/(c - a) and B = b - [(d - b)/(c - a)]a, so [etc.]"
> 
> I substituted A for the alpha symbol and B for the beta symbol.  My 
> question is, why "therefore"? How does he pull the values of A and B 
> out of those two equations? I understand where those two equations 
> come from, but I don't get the derivation of A and B.
> 
> This is not homework - which is a good thing, cause I'd flunking 
> right about now.
> 
> Thanks for any hints.

(Aa + B) - (Ac + B) = b - d

Aa - Ac = b - d

A = (b - d)/(a - c)
 
to start.
 




 11 Posts in Topic:
solving algebraic equations
OP <facetious_nickname  2008-02-20 23:56:43 
Re: solving algebraic equations
Paul Sperry <plsperry@  2008-02-21 01:24:14 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-21 09:03:23 
Re: solving algebraic equations
"[Mr.] Lynn Kurtz&qu  2008-02-21 17:11:43 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-21 11:51:51 
Re: solving algebraic equations
Virgil <Virgil@[EMAIL   2008-02-21 01:08:49 
Re: solving algebraic equations
Frederick Williams <&q  2008-02-21 13:22:04 
Re: solving algebraic equations
Stan Brown <the_stan_b  2008-02-22 03:34:56 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-22 15:27:24 
Re: solving algebraic equations
Stan Brown <the_stan_b  2008-02-23 04:19:38 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-23 10:59:39 

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