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Re: solving algebraic equations

by Frederick Williams <"Frederick Williams"@[EMAIL PROTECTED] Feb 21, 2008 at 01:22 PM

OP wrote:
> 
> On p. 58 & 59 of Spivak's Calculus, he says "Given two distinct
> points (a,b) and (c,d), find the linear function f whose graph goes
> through (a,b) and (c,d). This amounts to saying that f(a) = b and
> f(c) = d. If f is to be of the form f(x) = Aa + B, then we must have:
> 
> Aa + B = b;
> Ac + B = d;
> 
> therefore A = (d - b)/(c - a) and B = b - [(d - b)/(c - a)]a, so [etc.]"

It sounds as if Spivak expects his reader to know (at least the
rudiments of) linear algebra before he embarks on calculus; which is not
an unreasonable assumption.

Some authors, such as Protter and Morrey[1, 2] do the two in parallel,
but their books seem to be out of print.

How are things done now: in parallel or linear algebra followed by
calculus?

[1] Calculus and Analytic Geometry, A First Course, Addison-Wesley.
[2] Modern Mathematical Analysis, Addison-Wesley.

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Going forward at this moment in time a raft of measures 
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 11 Posts in Topic:
solving algebraic equations
OP <facetious_nickname  2008-02-20 23:56:43 
Re: solving algebraic equations
Paul Sperry <plsperry@  2008-02-21 01:24:14 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-21 09:03:23 
Re: solving algebraic equations
"[Mr.] Lynn Kurtz&qu  2008-02-21 17:11:43 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-21 11:51:51 
Re: solving algebraic equations
Virgil <Virgil@[EMAIL   2008-02-21 01:08:49 
Re: solving algebraic equations
Frederick Williams <&q  2008-02-21 13:22:04 
Re: solving algebraic equations
Stan Brown <the_stan_b  2008-02-22 03:34:56 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-22 15:27:24 
Re: solving algebraic equations
Stan Brown <the_stan_b  2008-02-23 04:19:38 
Re: solving algebraic equations
OP <facetious_nickname  2008-02-23 10:59:39 

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