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Education > Algebra help > Re: Newbie: hel...
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Re: Newbie: help needed with definition

by "Jack" <jj@[EMAIL PROTECTED] > Apr 25, 2008 at 08:45 PM

>> I am pairing values n with n'.
>> Let i_1 and i_2 be integers (whether distinct or not) such that  1<=i_1
&
>> i_2 <= y.
>
> Did you mean x <= i_1, i_2 <= y?  Because if you really
> meant the lower bound to be 1, x doesn't figure in your
> definitions of pairs (n, n') and therefore shouldn't be
> involved in any expression counting such pairs.

No, sorry; I meant in fact that  0 <= i_1, i_2 <= y-x+1.
Then I go on to say,  n=y-i_1 and n'=y'-i_2

>> There are (y-x)^2 possible pairs n and n'.
>
> This makes no sense until you've told us what n and n' are.

n is an integer in the interval [x,y] and n' is an integer in the inteval 
[x',y'].

>
>> This includes pairs
>> (n,n') such that n=y-i_1 and n'=y'-i_2, and also (n,n') such that
n=y-i_2
>> and n'=y-i_1.
>
> Do you mean that for each i_1 and i_2 in the range specified
> above, (y - i_1, y' - i_2)

Yes.


>> Let C be the set of the possible combinations of (n,n').
>> #C=(y-x)^2.
>
> If my interpretation is correct, #C is actually
> (y - x + 1)^2, since there are y - x + 1 integers in the
> range [x, y] (assuming that x and y are themselves integers
> and x <= y).

Quite right.


>> Define A' to be a subset of C, such that
>
>> a) #A' = y-x
>
>> b) y>x.
>
>> c) y'-x'=y-x
>
> This makes no sense: what are x' and y'?

x' is the lower bound and y' the upper bound of the interval [x',y'] .

With thanks.
 




 5 Posts in Topic:
Newbie: help needed with definition
"Jack" <jj@[  2008-04-25 18:26:42 
Re: Newbie: help needed with definition
"Brian M. Scott"  2008-04-25 15:18:24 
Re: Newbie: help needed with definition
"Jack" <jj@[  2008-04-25 20:45:45 
Re: Newbie: help needed with definition
"Jack" <jj@[  2008-04-27 02:29:45 
Re: Newbie: help needed with definition
"Jack" <jj@[  2008-04-27 13:07:24 

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tan12V112 Thu Dec 4 11:48:40 CST 2008.