Re: Question on logs (last one of the day, I promise)
by "[Mr.] Lynn Kurtz" <kurtz@[EMAIL PROTECTED]
>
May 2, 2008 at 02:00 AM
On Thu, 1 May 2008 12:13:24 -0700 (PDT), henrysun909@[EMAIL PROTECTED]
wrote:
>I realize this is probably a stupid question, but if one has an
>equation like
>
>2log3x = 2 + log3(x-2), how does one account for the "2 +" part of the
>equation on the left?
>
>Thanks in advance.
>
>Henry Sun
Assuming you mean 2 log_3(x) = 2 + log_3(x-2) where the _3 means base
3, collect both log terms on one side and use the following two
properties:
k log(x) = log (x^k) and log(a) - log(b) = log(a/b)
to get it into the form log_3(something) = 2. Then write the
equivalent exponential equation and solve a quadratic for x.
--Lynn
