Hi William,
Thank you for your comments concerning the subject line, your absolutely
correct. Sorry about that.
The question I wanted to solve was taken from a psychometric test and I
had 2 minutes to answer the question.
I realise that it could be resolved by factors, but in the time I had
and with calculators not allowed I thought it was quite a challenge. I
was just wondering if there was an obvious quick way to solve this that
I had not seen.
The factors for 2847 (compiled using a spreadsheet) are shown in the
list below, obviously as whole number entries. So the answer to the
problem is clearly 73 as the number of people that went on the trip and
$39.00 as the ticket cost ....
1423.5 2
949 3
711.75 4
569.4 5
474.5 6
406.7142857 7
355.875 8
316.3333333 9
284.7 10
258.8181818 11
237.25 12
219 13
203.3571429 14
189.8 15
177.9375 16
167.4705882 17
158.1666667 18
149.8421053 19
142.35 20
135.5714286 21
129.4090909 22
123.7826087 23
118.625 24
113.88 25
109.5 26
105.4444444 27
101.6785714 28
98.17241379 29
94.9 30
91.83870968 31
88.96875 32
86.27272727 33
83.73529412 34
81.34285714 35
79.08333333 36
76.94594595 37
74.92105263 38
73 39
71.175 40
69.43902439 41
67.78571429 42
66.20930233 43
64.70454545 44
63.26666667 45
61.89130435 46
60.57446809 47
59.3125 48
58.10204082 49
56.94 50
55.82352941 51
54.75 52
53.71698113 53
52.72222222 54
51.76363636 55
50.83928571 56
49.94736842 57
49.0862069 58
48.25423729 59
47.45 60
46.67213115 61
45.91935484 62
45.19047619 63
44.484375 64
43.8 65
43.13636364 66
42.49253731 67
41.86764706 68
41.26086957 69
40.67142857 70
40.09859155 71
39.54166667 72
39 73
38.47297297 74
37.96 75
37.46052632 76
36.97402597 77
36.5 78
36.03797468 79
35.5875 80
35.14814815 81
34.7195122 82
34.30120482 83
33.89285714 84
33.49411765 85
33.10465116 86
32.72413793 87
32.35227273 88
31.98876404 89
31.63333333 90
31.28571429 91
30.94565217 92
30.61290323 93
30.28723404 94
29.96842105 95
29.65625 96
29.35051546 97
29.05102041 98
28.75757576 99
28.47 100
28.18811881 101
Thank you
Regards
Martin.
William Elliot wrote:
> On Sat, 10 May 2008, Martin wrote:
>
>> Sorry to be a pain but can you help me with this problem.....
>>
> Use a subject more informative than help.
> Those help posts don't give much incentive reply,
> not do they inform us if it's we handle.
>
>> Between 50 and 100 people hired a private carriage for a railway trip,
>> and they paid a total of $2847.00. Each person paid the same amount,
>> which was an exact number of dollars.
>
>> How many people went on the trip?
>>
> Hint: what are the factors of 2847?
>
> What was the cost of a ticket?
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