Talk About Network

Google


Register and Login
Nick
Password
Register create new account Sign up is FREE and you can post replies, new topics, bookmark posts and more!
Recover lost password


Education > Algebra help > New Q on expres...
Latest [ Topics | Posts ] Archive Post A New Topic Post a Reply
<< Topic < Post Post 1 of 5 Topic 2058 of 2164
Post > Topic >>

New Q on expression

by "Jack" <jj@[EMAIL PROTECTED] > Jul 14, 2008 at 11:10 PM

I'm trying to define a set A. I want to say that, given an integer z, every

set A has 6 members, these being pairs of integers (z+(k+1), z-(k+1)),(z 
+(k+2,), z-(k+2)),(z+(k+3,),z-(k+3)),(z+(k+4),z-(k+4)), (z+(k+5),z-(k+5)),

(z+(k+6),z-(k+6)). Can someone advise me on the best way to write it?
With thanks.
 




 5 Posts in Topic:
New Q on expression
"Jack" <jj@[  2008-07-14 23:10:33 
Re: New Q on expression
Virgil <Virgil@[EMAIL   2008-07-14 16:32:48 
Re: New Q on expression
"Jack" <jj@[  2008-07-15 13:49:26 
Re: New Q on expression
Frederick Williams <fr  2008-07-15 15:08:34 
Re: New Q on expression
Virgil <Virgil@[EMAIL   2008-07-15 15:13:24 

Post A Reply:
  Go here to Signup

AddThis Feed Button


About - Advertising - Contact - Frequently Asked Questions - Privacy Policy - Terms of Use - Signup

Contact
tan12V112 Thu Dec 4 14:46:17 CST 2008.