On Sat, 19 Jul 2008 19:58:13 +0100, Jack <jj@[EMAIL PROTECTED]
>
wrote in <news:8Pqgk.9112$X72.6423@[EMAIL PROTECTED]
> in
alt.algebra.help:
>>> Well how would I do it then? I have defined p and q as
>>> members of J and now I want to say that I want to
>>> consider the case where B is dependent upon all possible
>>> p and q.
> Every possible member of J can be considered a prime p,
> and, also, every possible member of J can be considered
> a prime q; the sole criterion -- if it's worth anything,
> what with all the members ultimately being both a p and
> a q -- is that when considering one member as p, a
> different one is considered to be q.
In English: p and q always represent distinct members of J.
>> First you'll have to explain what you mean by this.
>> Precisely HOW is the set to depend on all of the members of
>> J? Under exactly what conditions does an integer b get to
>> belong to the set that you want to call B(x, J)?
> The integer b is a member of B if and only if any p or q
> divide n in [x,y] such that n=(y+1)/2-b, or n=
> (y+1)/2+b.
This is incomprehensible.
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