by William Elliot <marsh@[EMAIL PROTECTED]
>
Jul 21, 2008 at 12:20 AM
On Sun, 20 Jul 2008 henrysun909@[EMAIL PROTECTED]
wrote:
> Let's say that a function f(x) = x^.5 (square root of x) is graphed on
> the coordinate axes and that a line p is drawn from the origin to
> (x,y) where x is the number whose square root is being derived and y
> is that number.
>
> How does one estimate the slope of the line p as it moves along the
> curve graphed by f(x) = x^.5?
>
slope p = y/x = (sqr x)/x = 1/sqr x.
