Re: Can someone help me?

On Sun, 20 Jul 2008 09:28:44 -0700 (PDT), revdorisj@[EMAIL PROTECTED]
 wrote:

>One of the students in my church is struggling with his algebra
>homework.  Can someone show me the steps to solving these two
>problems:
>
>A.  Graph the inverse of y = (2/3) to the x power.
>
>B.  Simplify (sorry this one is hard to lay out):
>
>1/a squared - 1/b squared in the numerator
>
>a to the -2 + 2ab to the -1 + b to the -2 in the denominator
>
>Reverend Doris
 First---you're lying---god'll get ya!! REVEREND!
Have the student go talk to his/her instructor. Only the stupid
don't get help from the person paid to give them help!
 Finally, lear how to write math in text.
 A. graph the inverse of y= (2/3)^x
   etc   exponents are denoted bt "^" division by "/"
multiplication by "*"