by Pfsszxt@[EMAIL PROTECTED]
Jul 21, 2008 at 01:37 PM
On Sun, 20 Jul 2008 09:28:44 -0700 (PDT), revdorisj@[EMAIL PROTECTED]
wrote:
>One of the students in my church is struggling with his algebra
>homework. Can someone show me the steps to solving these two
>problems:
>
>A. Graph the inverse of y = (2/3) to the x power.
>
>B. Simplify (sorry this one is hard to lay out):
>
>1/a squared - 1/b squared in the numerator
>
>a to the -2 + 2ab to the -1 + b to the -2 in the denominator
>
>Reverend Doris
Help you? Or the student for whom you write_--sure !!!!!!!!
