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An exact simplification challenge - 53 (elementary functions'

by Vladimir Bondarenko <vb@[EMAIL PROTECTED] > Mar 19, 2008 at 03:32 PM

Hello computer algebra Fighter the Earthling,

Train hard, fight easy! The Last Battle is coming!

Go and do***ent our human's intelligence superiority over the
dreadful (striped!) Computers coming.... maybe driving at our
beer, cheese and Southern hot sausages, who knows?!

My carbon-based brethren worldwide, it is only daily training,
training, and more training that will allow us to curb the
aggressors, and stop once and for all the advance of the World
Silicon/Superconductive/Qbit Evil and this way to rescue the
Universe.... along with our eatables!

Back to the training exercises...

Is there an Insensible-To-Fear Human Warrior the Simplifier to
come up with a succession of CAS commands to squeeze this very,
very, very much

((-1)^(1/4)*((1-I)*Pi+I*(Pi-ArcTan[4])+I*ArcTan[4]+(2*I)*ArcTan
[2+(1-I)*Sqrt[2]]-2*ArcTan[2+(1+I)*Sqrt[2]]+I*ArcTan[(-6+2*Sqrt
[2])/(-1+2*Sqrt[2])] - I*ArcTan[(2+2*Sqrt[2])/(1+2*Sqrt[2])]-I*
ArcTan[(5+2*Sqrt[2])/(4+2*Sqrt[2])]+I*ArcTan[(5+4*Sqrt[2])/(4+4
*Sqrt[2])] +I*ArcTan[(6+3*Sqrt[3])/(6+2*Sqrt[3])]-I*ArcTan[(69+
12*Sqrt[3])/(114 -22*Sqrt[3])]+2*ArcTanh[(14-4*Sqrt[3])/(20-11*
Sqrt[3])] + (2*I)*ArcTanh[((6+4*I)+2*Sqrt[3])/((3+4*I)-(1+2*I)*
Sqrt[3])]+(1+I)*Log[-6+7*Sqrt[3]]-I*((-2*I)*Pi+I*(Pi-ArcCot[4])
+I*(Pi+ArcTan[(-1+2*Sqrt[2])/(-6+2*Sqrt[2])])-Log[17]/2+Log[(-6
+2*Sqrt[2])^2 +(-1+2*Sqrt[2])^2]/2)+Log[(-6+2*Sqrt[2])^2+(-1+2*
Sqrt[2])^2]/2 + I*( (-I)*ArcCot[4]+I*ArcTan[(1+2*Sqrt[2])/(2+2*
Sqrt[2])]-Log[17]/2+Log[(1+2*Sqrt[2])^2+(2+2*Sqrt[2])^2]/2)-Log
[(1+2*Sqrt[2])^2+(2+2*Sqrt[2])^2]/2+I*(I*ArcTan[(4+2*Sqrt[2])/(
5+2*Sqrt[2])]+Log[(4+2*Sqrt[2])^2+(5+2*Sqrt[2])^2]/2)-Log[(4+2*
Sqrt[2])^2 + (5+2*Sqrt[2])^2]/2-I*(I*ArcTan[(4+4*Sqrt[2])/(5+4*
Sqrt[2])] + Log[(4 + 4*Sqrt[2])^2+(5+4*Sqrt[2])^2]/2)+Log[(4+4*
Sqrt[2])^2 + (5+4*Sqrt[2])^2]/2+I*(I*ArcTan[(6+2*Sqrt[3])/(6+3*
Sqrt[3])]+Log[(6+2*Sqrt[3])^2+(6+3*Sqrt[3])^2]/2)+Log[(6+2*Sqrt
[3])^2 +(6+3*Sqrt[3])^2]/2-I*(I*ArcTan[(114-22*Sqrt[3])/(69+12*
Sqrt[3])]+Log[(114-22*Sqrt[3])^2+(69+12*Sqrt[3])^2]/2)-Log[(114
-22*Sqrt[3])^2+(69+12*Sqrt[3])^2]/2))/4

(* = 0.87041.... *)

                         ?
Best wishes,

Vladimir Bondarenko

VM and GEMM architect
Co-founder, CEO, Mathematical Director

http://www.cybertester.com/
 Cyber Tester, LLC
http://maple.bug-list.org/
  Maple Bugs Encyclopaedia
http://www.CAS-testing.org/
 CAS Testing

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 4 Posts in Topic:
An exact simplification challenge - 53 (elementary functions'
Vladimir Bondarenko <v  2008-03-19 15:32:00 
Re: An exact simplification challenge - 53 (elementary functions
giovanni resta <g.rest  2008-03-20 00:00:28 
Re: An exact simplification challenge - 53 (elementary functions
Robert Israel <israel@  2008-03-19 19:00:06 
Re: An exact simplification challenge - 53 (elementary functions
hrubin@[EMAIL PROTECTED]   2008-03-20 14:07:10 

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tan12V112 Sun Jul 20 17:53:37 CDT 2008.