Yes, you're right. I'll have to leave the intersecting hyperbolas for
another time. For now all I have is the intersection of 3 spheres of
known
centers and known radii.
"Laurence Reeves" <l@[EMAIL PROTECTED]
> wrote in message
news:2oSdnaC6Adypc2TanZ2dneKdnZydnZ2d@[EMAIL PROTECTED]
> Jon G. wrote:
>> "Laurence Reeves" <l@[EMAIL PROTECTED]
> wrote in message
>> news:lY2dnX5q-6PrqWTanZ2dnUVZ8qqlnZ2d@[EMAIL PROTECTED]
>>> Jon G. wrote:
>>>> "Laurence Reeves" <l@[EMAIL PROTECTED]
> wrote in message
>>>> news:crOdnbwQqc7xUGXanZ2dneKdnZydnZ2d@[EMAIL PROTECTED]
>>>>> jmorriss@[EMAIL PROTECTED]
wrote:
>>>>>> On Apr 5, 10:20 pm, "U7 1000k" <y@[EMAIL PROTECTED]
> wrote:
>>>>>>> GPS Solution
>>>>>>> Nested Parabolas
>>>>>>>
>>>>>>> http://mypeoplepc.com/members/jon8338/math/
>>>>>> So, where do we buy these GPS receivers with built in cesium or
>>>>>> rubidium atomic clocks?
>>>>> Hey! Not fair. I only got one parabola, along with a bunch of other
>>>>> bendy lines. The label said there was gonna be more than one
parabola
>>>>> in the nest. I feel cheated.
>>>>>
>>>> Look again, blind spotty.
>>>>
>>>> The updated site for those requiring spoon feeding is,
>>>>
>>>> http://mypeoplepc.com/members/jon8338/math/
>>>>
>>>>
>>> Strange person.
>>>
>>> In the GPS instance, you assert that you have three distances. You do
>>> not. You have three timestamps, transmitted by the satellites. As
>>> jmorriss observed, you have no accurate timestamp at your location,
thus
>>> you only know the three distances in a form d0+C, d1+C and d2+C, where
C
>>> is a constant you have only rather inaccurate knowledge of.
>>>
>>> In the latter case, I assumed that you were using the word "parabola"
in
>>> a rigorous mathematical sense, hence only your blue, m=0 curve is a
>>> parabola, and is not "nested".
>>>
>>> If you are only using the term "parabola" in the loose sense of a
curve
>>> that vaguely resembles a parabola, I would admit that the curves with
>>> m>0 are tolerable, but the self-intersecting curves with m<0 are
>>> probably not. I guess that would be a matter of taste.
>>>
>> Three satellites with synchronous Cesium clocks transmit
> > and the receiver records their time stamps. A moment later they
> transmit
> > again and the receiver records a second set of time stamps.
> >
> > distance = (time)(speed of light)
> >
> > and the three distances from the receiver to the satellites are known.
> >
> >
> No.
>
> Assuming that your "A moment" is the millisecond you suggest in your
other
> post, you will now have one set of three timestamps, and the same three
> timestamps, each incremented by one millisecond. These tell you nothing
> new.
>
> --
> Lau AS! d-(!) a++ c++++ p++ t+ f-- e++ h+ r--(+) n++(*) i++ P- m++
> ASC Decoder at <http://www32.brinkster.com/ascdecode/>
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