Hello dear computer algebra Fan the Earthling,
My carbon-based brother and sisters, wake up! Waaaatch out,
those formidable (striped!) Computers are already stretching
their silicon hands over our the planet, the cradle of the
(only?) spark of Intelligence in this Universe!
Who knows, maybe, tomorrow or the day after tomorrow, if
we - if YOU - do not stop 'em, they rob us of tomato juice,
potato chips, and what's the worst, our beer (God forbid)!
Train hard, train hard, as famous Russian Field Marshal
Alexandr Suvorov has it, - to fight in apple pie order!
Go and show to these stupid cold chips and some professors,
that you really have 'nough little gray cells to keep all
under control! Stack 'em, pack 'em and rack 'em!
So, is there a Daring Integrator the Warrior who can discover
a string of a CAS commands to get the nice exact value of
int(-sqrt(2)*z*sqrt((sqrt(z^2+2*z+2)-sqrt(z^2+1)+1)/(sqrt(2)*
sqrt(sqrt(z^2+1)-z)+sqrt(z^2+1)+1))/(z^2+1)^2+sqrt(2)*(z^2-1)
*sqrt((sqrt(z^2+2*z+2)+sqrt(z^2+1)-1)/(sqrt(2)*sqrt(sqrt(z^2+
1)-z)+sqrt(z^2+1)+1))/(2*(z^2+1)^2)+sqrt(2)*z*sqrt((sqrt(z^2-
2*z+2)-sqrt(z^2+1)+1)/(sqrt(2)*sqrt(sqrt(z^2+1)+z)+sqrt(z^2+1
)+1))/(z^2+1)^2+sqrt(2)*(z^2-1)*sqrt((sqrt(z^2-2*z+2)+sqrt(z^
2+1)-1)/(sqrt(2)*sqrt(sqrt(z^2+1)+z)+sqrt(z^2+1)+1))/(2*(z^2+
1)^2)-(sqrt(2)*(z^2-1)*sqrt(-(sqrt(z^2+2*z+2)-sqrt(z^2+1)+1)/
(sqrt(2)*sqrt(sqrt(z^2+1)-z)+sqrt(z^2+1)+1))/(2*(z^2+1)^2)+sq
rt(2)*z*sqrt(-(sqrt(z^2+2*z+2)+sqrt(z^2+1)-1)/(sqrt(2)*sqrt(s
qrt(z^2+1)-z)+sqrt(z^2+1)+1))/(z^2+1)^2+sqrt(2)*(z^2-1)*sqrt(
-sqrt(z^2-2*z+2)+sqrt(z^2+1)-1)/(2*(z^2+1)^2*sqrt(sqrt(2)*sqr
t(sqrt(z^2+1)+z)+sqrt(z^2+1)+1))-sqrt(2)*z*sqrt(-sqrt(z^2-2*z
+2)-sqrt(z^2+1)+1)/((z^2+1)^2*sqrt(sqrt(2)*sqrt(sqrt(z^2+1)+z
)+sqrt(z^2+1)+1))), z= 0..infinity);
?
Cheers,
Vladimir Bondarenko
Fighter for Freedom and Southern Hot Sausages
VM and GEMM architect
Co-founder, CEO, Mathematical Director
http://www.cybertester.com/
Cyber Tester, LLC
http://maple.bug-list.org/
Maple Bugs Encyclopaedia
http://www.CAS-testing.org/
CAS Testing
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