Hello computer algebra Buff the Earthling,
You've spotted that we keep preparing for the Ultimate Battle...
Now you? Ready to fight for our C12-based Human Civilization?
(If not, think again, and get ready!)
The Last Combat against the bad (striped!) Computers is near!
As Field Marshal Suvorov teaches us, Train hard, fight easy!
(don't give your little gray cells to get too slow... or else
the wicked (striped!) Computers will rob us!)
So, is there a Valiant Warrior the Simplifier to invent a string
of CAS commands to squeeze (20+ times) this expression
-(1/120*(30-6*5^(1/2))^(1/2)+1/120*5^(1/2)-1/40)*arctan((8*(30-6
*5^(1/2))^(1/2)-8*5^(1/2)-8)/(8*(10-2*5^(1/2))^(1/2)+8*3^(1/2)*(
5^(1/2)+1)))+(1/120*(30-6*5^(1/2))^(1/2)-1/120*5^(1/2)+1/40)*arc
tan((8*(30-6*5^(1/2))^(1/2)+8*5^(1/2)+8)/(8*(10-2*5^(1/2))^(1/2)
-8*3^(1/2)*(5^(1/2)+1)))-(1/120*(30+6*5^(1/2))^(1/2)+1/120*5^(1/
2)+1/40)*arctan((8*(30+6*5^(1/2))^(1/2)-8*5^(1/2)+8)/(8*(10+2*5^
(1/2))^(1/2)+8*3^(1/2)*(5^(1/2)-1)))-(1/120*(30+6*5^(1/2))^(1/2)
-1/120*5^(1/2)-1/40)*arctan((8*(30+6*5^(1/2))^(1/2)+8*5^(1/2)-8)
/(8*(10+2*5^(1/2))^(1/2)-8*3^(1/2)*(5^(1/2)-1)))+(1/240*(30+6*5^
(1/2))^(1/2)+1/240*5^(1/2)+1/80)*arctan(((10-2*5^(1/2))^(1/2)+3^
(1/2)*(5^(1/2)+1))/((30-6*5^(1/2))^(1/2)-5^(1/2)-1))+(1/240*(30+
6*5^(1/2))^(1/2)-1/240*5^(1/2)-1/80)*arctan(((10-2*5^(1/2))^(1/2
)-3^(1/2)*(5^(1/2)+1))/((30-6*5^(1/2))^(1/2)+5^(1/2)+1))-(1/240*
(30-6*5^(1/2))^(1/2)-1/240*5^(1/2)+1/80)*arctan(((10+2*5^(1/2))^
(1/2)+3^(1/2)*(5^(1/2)-1))/((30+6*5^(1/2))^(1/2)-5^(1/2)+1))+(1/
240*(30-6*5^(1/2))^(1/2)+1/240*5^(1/2)-1/80)*arctan(((10+2*5^(1/
2))^(1/2)-3^(1/2)*(5^(1/2)-1))/((30+6*5^(1/2))^(1/2)+5^(1/2)-1))
+Pi*(1/24*(15+6*5^(1/2))^(1/2)+7/120*5^(1/2)+1/10)
?
Best wishes,
Vladimir Bondarenko
VM and GEMM architect
Co-founder, CEO, Mathematical Director
http://www.cybertester.com/
Cyber Tester, LLC
http://maple.bug-list.org/
Maple Bugs Encyclopaedia
http://www.CAS-testing.org/
CAS Testing
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