Hummm... your answer is asolutely correct!
However, in my Derive 6.1 with standard factory settings
(the settings by default) it simplifies to
-(SQRT(1/480-SQRT(5)/2400)+SQRT(5)/
120-1/40)*ATAN((SQRT(1920-384*SQRT(5))-8*S~
QRT(5)-8)/(SQRT(640-128*SQRT(5))+8*SQRT(3)*(SQRT(5)+1)))+(SQRT(1/480-
SQRT(5)/~
2400)-SQRT(5)/120+1/40)*ATAN((SQRT(1920-384*SQRT(5))+8*SQRT(5)+8)/
(SQRT(640-1~
28*SQRT(5))-8*SQRT(3)*(SQRT(5)+1)))-(SQRT(SQRT(5)/2400+1/480)+SQRT(5)/
120+1/4~
0)*ATAN((SQRT(384*SQRT(5)+1920)-8*SQRT(5)+8)/
(SQRT(128*SQRT(5)+640)+8*SQRT(3)~
*(SQRT(5)-1)))-(SQRT(SQRT(5)/2400+1/480)-SQRT(5)/
120-1/40)*ATAN((SQRT(384*SQR~
T(5)+1920)+8*SQRT(5)-8)/(SQRT(128*SQRT(5)+640)-8*SQRT(3)*(SQRT(5)-1)))+
(SQRT(~
SQRT(5)/9600+1/1920)+SQRT(5)/240+1/80)*ATAN((SQRT(10-2*SQRT(5))
+SQRT(3)*(SQRT~
(5)+1))/(SQRT(30-6*SQRT(5))-SQRT(5)-1))+(SQRT(SQRT(5)/9600+1/1920)-
SQRT(5)/24~
0-1/80)*ATAN((SQRT(10-2*SQRT(5))-SQRT(3)*(SQRT(5)+1))/
(SQRT(30-6*SQRT(5))+SQR~
T(5)+1))-(SQRT(1/1920-SQRT(5)/9600)-SQRT(5)/
240+1/80)*ATAN((SQRT(2*SQRT(5)+10~
)+SQRT(3)*(SQRT(5)-1))/(SQRT(6*SQRT(5)+30)-SQRT(5)+1))+(SQRT(1/1920-
SQRT(5)/9~
600)+SQRT(5)/240-1/80)*ATAN((SQRT(2*SQRT(5)+10)-SQRT(3)*(SQRT(5)-1))/
(SQRT(6*~
SQRT(5)+30)+SQRT(5)-1))+pi*(SQRT(SQRT(5)/96+5/192)+7*SQRT(5)/120+1/10)
8-(
Are your settings the standard ones?
If not what are your settings?
On Apr 26, 2:36=A0am, cliclic...@[EMAIL PROTECTED]
wrote:
> Vladimir Bondarenko schrieb:
>
>
>
>
>
> > Hello computer algebra Buff the Earthling,
>
> > You've spotted that we keep preparing for the Ultimate Battle...
> > Now you? =A0Ready to fight for our C12-based Human Civilization?
>
> > (If not, think again, and get ready!)
>
> > The Last Combat against the bad (striped!) Computers is near!
>
> > As Field Marshal Suvorov teaches us, Train hard, fight easy!
> > (don't give your little gray cells to get too slow... or else
> > the wicked (striped!) Computers will rob us!)
>
> > So, is there a Valiant Warrior the Simplifier to invent a string
> > of CAS commands to squeeze (20+ times) this expression
>
> > -(1/120*(30-6*5^(1/2))^(1/2)+1/120*5^(1/2)-1/40)*arctan((8*(30-6
> > *5^(1/2))^(1/2)-8*5^(1/2)-8)/(8*(10-2*5^(1/2))^(1/2)+8*3^(1/2)*(
> > 5^(1/2)+1)))+(1/120*(30-6*5^(1/2))^(1/2)-1/120*5^(1/2)+1/40)*arc
> > tan((8*(30-6*5^(1/2))^(1/2)+8*5^(1/2)+8)/(8*(10-2*5^(1/2))^(1/2)
> > -8*3^(1/2)*(5^(1/2)+1)))-(1/120*(30+6*5^(1/2))^(1/2)+1/120*5^(1/
> > 2)+1/40)*arctan((8*(30+6*5^(1/2))^(1/2)-8*5^(1/2)+8)/(8*(10+2*5^
> > (1/2))^(1/2)+8*3^(1/2)*(5^(1/2)-1)))-(1/120*(30+6*5^(1/2))^(1/2)
> > -1/120*5^(1/2)-1/40)*arctan((8*(30+6*5^(1/2))^(1/2)+8*5^(1/2)-8)
> > /(8*(10+2*5^(1/2))^(1/2)-8*3^(1/2)*(5^(1/2)-1)))+(1/240*(30+6*5^
> > (1/2))^(1/2)+1/240*5^(1/2)+1/80)*arctan(((10-2*5^(1/2))^(1/2)+3^
> > (1/2)*(5^(1/2)+1))/((30-6*5^(1/2))^(1/2)-5^(1/2)-1))+(1/240*(30+
> > 6*5^(1/2))^(1/2)-1/240*5^(1/2)-1/80)*arctan(((10-2*5^(1/2))^(1/2
> > )-3^(1/2)*(5^(1/2)+1))/((30-6*5^(1/2))^(1/2)+5^(1/2)+1))-(1/240*
> > (30-6*5^(1/2))^(1/2)-1/240*5^(1/2)+1/80)*arctan(((10+2*5^(1/2))^
> > (1/2)+3^(1/2)*(5^(1/2)-1))/((30+6*5^(1/2))^(1/2)-5^(1/2)+1))+(1/
> > 240*(30-6*5^(1/2))^(1/2)+1/240*5^(1/2)-1/80)*arctan(((10+2*5^(1/
> > 2))^(1/2)-3^(1/2)*(5^(1/2)-1))/((30+6*5^(1/2))^(1/2)+5^(1/2)-1))
> > +Pi*(1/24*(15+6*5^(1/2))^(1/2)+7/120*5^(1/2)+1/10)
>
> > =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 ?
> > Best wishes,
>
> > Vladimir Bondarenko
>
> It simplifies to
>
> Pi*(Sqrt[6=B7Sqrt[5] + 15]/30 + Sqrt[5]/15 + 1/10)
>
> in a fraction of a second on Derive 6.10.
>
> Martin.
>
> Forgot to "translate" the square roots in my first reply!- Hide quoted
tex=
t -
>
> - Show quoted text -
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