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Education > Math Recreational > Root of Diverge...
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Root of Divergent Series

by "Jon G." <jon8338@[EMAIL PROTECTED] > May 18, 2008 at 05:54 AM

Conventions

|E| is the magnitude of vector E.
all limits are as n approaches infinity
ln e = 1

The power series 1 + x + x^2 + x^3 + ... + x^n  diverges when
x>=1 and has the root,

x = lim ln[(n!(n+1)|E|^2 - n!e^2)/(n!e-(n+1))]

where \

|E|^2=(1/0!)^2 + (1/1!)^2 + (1/2!)^2 + (1/3!)^2 + ... + (1/n!)^2

Proof

1+lim{(1+2+3+...+n)ln[(n!(n+1)|E|^2 - n!e^2)/(n!e-(n+1))]=0

lim ln[(n!(n+1)|E|^2 - n!e^2)/(n!e-(n+1))]=-lim 1/(1+2+3+...+n)=0

lim [(n!(n+1)|E|^2 - n!e^2)/(n!e-(n+1))]=1

lim 1/(n!e-(n+1)) = lim 1/(n!(n+1)|E|^2 - n!e^2)

0=0

E.O.P.
 




 2 Posts in Topic:
Root of Divergent Series
"Jon G." <jo  2008-05-18 05:54:10 
Re: Root of Divergent Series
William Elliot <marsh@  2008-05-19 03:25:46 

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tan12V112 Sat Oct 11 22:34:50 CDT 2008.