In article
<31814627.1209872397837.JavaMail.jakarta@[EMAIL PROTECTED]
>,
amu <amu786la@[EMAIL PROTECTED]
> wrote:
> Let B = {(x, sin(1/x)): x in R-{0}}
> Theorem: Putting a limit point of a connected set into a connected set
does
> not disconnect the set (i.e., the set remains connected).
> Thus, since B is connected and (0,0)
How is B connected? One can separate it into the disjoint open sets
{(x,y): x,y in R and x > 0} and {(x,y): x,y in R and x < 0}
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