On Sat, 10 May 2008 SneakyElf@[EMAIL PROTECTED]
wrote:
> ok, here's the problem.. prove <u,v> = 0 iff ||u|| less than or equal
> to ||u + av||
> where u,v in V and a is in F.
Let u = v = (1,0), a = 1. Then ||u|| = 1 <= ||u + v|| = 2
and <u,v> /= 0. Thus the problem has vanished as it's false.
Here's another problem. Do you know how to capitalize?
Then do it. Don't look stupid. It's unbefitting of elves.
> so, <u,v> = 0 iff <v, u> = 0
Of course, isn't the inner product symmetric?
> squaring both sides ||u|| ^2 = ||u|| ^2 + |a|^2 ||v||^2
> = <u + av, u + av>
> = <u, u> + a <v,v> + .....?
>
Squaring both sides of what?
> it is a simple problem, and any pointers to solution will be
> appreciated.
>
Demonstrate your academic intelligence, capitalize your sentences.
It won't stimulate my rudeness nor, as I frequently do, just skip
it for being ill written. There are often more posts
each night than I can read. Thus the sloppy, non-thinking
posts are answered last if at all. Tonight was,, in your favor,
a slow night, thus upon the third or fourth time through the groups,
I got around to your answering post.
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