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Re: x = ?

by Virgil <Virgil@[EMAIL PROTECTED] > May 10, 2008 at 04:46 PM

In article <F6CdnWuhE7s9mLvVnZ2dnUVZ_ojinZ2d@[EMAIL PROTECTED]
>,
 "Jon G." <jon8338@[EMAIL PROTECTED]
> wrote:

> 1 + x + x^2 + x^3 + ... + x^n = 0
> 
> x = ? 

n = 1 -> x = -1
n = 2 -> x = (-1 +/- sqrt(3))/2
n = 3 -> n = -1 or x = +/- i

In general, for a given positive integer n, the solutions to your 
equation are the (n+1)th roots of  1  other than 1.




 10 Posts in Topic:
x = ?
 "Jon G." <jo  2008-05-10 16:20:04 
Re: x = ?
 Ray Vickson <RGVickson  2008-05-10 14:12:24 
Re: x = ?
 metaweta@[EMAIL PROTECTED  2008-05-10 14:39:31 
Re: x = ?
 David C. Ullrich <dull  2008-05-11 11:27:58 
Re: x = ?
 Dave <dave_and_darla@[  2008-05-10 14:41:26 
Re: x = ?
 Virgil <Virgil@[EMAIL   2008-05-10 16:46:56 
Re: x = ?
 Bart Goddard <goddardb  2008-05-10 23:45:33 
Re: x = ?
 William Elliot <marsh@  2008-05-10 22:34:09 
Re: x = ?
 Pfsszxt@[EMAIL PROTECTED]  2008-05-11 08:06:20 
Re: x = ?
 Pfsszxt@[EMAIL PROTECTED]  2008-05-17 18:54:36 

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