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Education > Math > Re: help with a...
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Re: help with acceleration and deceleration

by Odysseus <odysseus1479-at@[EMAIL PROTECTED] > Jul 8, 2008 at 02:19 AM

In article <Mbuck.30031$s77.28836@[EMAIL PROTECTED]
>,
 Bill <Bill@[EMAIL PROTECTED]
> wrote:

> Odysseus,

> > I get the impression Bill is after a sigmoid shape: perhaps 
> > something like
> > 
> > s = (9/20)(curt((t/5)-1) + 11/9)

> That is correct, I am after a Sigmoid shape. I didn't quite 
> understand your function, what is curt?

Sorry if that was obscure. I meant the cube root:

s = (9/20)(((t/5) - 1)^(1/3) + 11/9)

> Can your function be modified so that it only accelerates at the 
> intro or decelerates at the outro or both?

Yes: the first two (substituting "mostly" for "only") respectively by 
removing or doubling the "- 1" under the cube root, then tweaking the 
scale and offset constants to suit -- but a half-parabola would be 
simpler. I'm not quite sure what you mean by "both".

-- 
Odysseus
 




 6 Posts in Topic:
help with acceleration and deceleration
Bill <Bill@[EMAIL PROT  2008-07-01 23:10:27 
Re: help with acceleration and deceleration
Bill <Bill@[EMAIL PROT  2008-07-02 16:02:30 
Re: help with acceleration and deceleration
Mensanator <mensanator  2008-07-02 16:27:53 
Re: help with acceleration and deceleration
Odysseus <odysseus1479  2008-07-04 06:16:59 
Re: help with acceleration and deceleration
Bill <Bill@[EMAIL PROT  2008-07-07 15:34:33 
Re: help with acceleration and deceleration
Odysseus <odysseus1479  2008-07-08 02:19:56 

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